Question

three unbiased coins are tossed together what is the probability of getting
a) two head b)at least two head c)at most 2 head d)no tail
✔✔✔✔✔✔✔✔✔✔✔✔✔✔✔ ✔ ✔ ✔ ✔ with solvation tooooo​

Answer 1

hey mate here is your answer


When 3 unbiased coins are tossed, the sample space is {HHH, HTH, HHT, THH, THT, TTH, HTT, TTT] = 8

Event of getting two heads = {HTH, HHT, THH} = 3

P(Two Heads) = 3/8

Event of getting At least two heads (two or more than 2 heads) = {HHH, HTH, HHT, THH} = 4

P(At least Two Heads) = 4/8 = 1/2

Event of getting No heads = {TTT} = 1

P(No Heads) = 1/8


hope it help
mark as brainliest

Answer 2

Step-by-step explanation:

Total number of coins = 3

Possible outcomes n(S) = {HHH, TTT, TTH, THT, HTT, THH, HTH, HHT}

                                        = 8

(a) Two heads:

Let E = getting two heads

n(E) = {HHT, HTH, TTH} = 3

P(E) = n(E)/n(S)

      = 3/8

(b) At least two heads:

Let E = At least two heads.

n(E) = {THH, HTH, HHT, HHH} = 4

P(E) = 4/8

       = 1/2.

(c) at most 2 heads:

Let E = at most 2 heads.

n(E) = {TTH, THT, HTT, THH, HTH, HHT, HHH} = 7

P(E) = 7/8

(d) No Tail:

E = no tail

n(E) = {HHH}

P(E) = 1/8

Hope it helps!