Three unbiased coins are tossed. what is the probability of getting at most one heads
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= one head or no head
= 3(1/8)+1/8
= 1/2
and we can say it directly as only four case are possible with same probability
and two are favorable cases
so the prob of two is 2/4 or 1/2
= 3(1/8)+1/8
= 1/2
and we can say it directly as only four case are possible with same probability
and two are favorable cases
so the prob of two is 2/4 or 1/2
Answered by
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solution
total number of possible outcomes = 8
No. of favourable outcomes= 3
p= 3/8.
total number of possible outcomes = 8
No. of favourable outcomes= 3
p= 3/8.
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