Question

Three unbiased couns are tossed together .
find the probability of getting (1)one head

(2) all heads
(3)all tails
(4)at least one head

Answer 1

Answer:

Step-by-step explanation:

For fairly tossed fair coins the number of possible outcomes = 2^3 =8.

They are: TTT, HTT, THT, TTH, HHT, HTH, THH, HHH.

(i) Getting 3H…..1 way. Probability = 1/8.

(ii) Getting 2H….3 ways. Probability = 3/8.

(iii) Getting 1H….3 ways. Probability = 3/8.

Getting____0H…..1 way. Probability = 1/8.

(iv) Getting at least 1H probability = probability of either 1H, 2H or 3H = (1/8)+(3/8)+(3/8) = 7/8.

(v) Getting at least 2H probability = probability of either 2H or 3H = (3/8)+(1/8) = 1/2.

(vi) Getting at most 2H probability = probability of either 0H, 1H or 2H = (1/8)+(3/8)+(3/8) = 7/8.