Question

Three uncharged capacitors are connected with a battery as shown in the figure. The work done by the battery in fully charging the capacitors will be??​

Answer 1

When the switch is open, the equivalent capacitance C 1 =( 24 )μFCharge flown through the battery = 34 ×30=40μCWhen switch is closeC 1′ =2μFq 1 =2×30=60μCHence, 20μC extra charge flows when S is closedWork done by the battery =20×10 −6 ×30=0.6mJWhen switch is closed, it is short circuited. Hence all the charge flows through S.