Three vertices of a parallelogram taken in order are (1,2), (0,4) and (3,7) . Find the fourth vertice.
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Let A-1,-6, B2,-5 and C7, 2 be the vertices of the parallelogram ABCD.
Let the coordinates of D be (x, y).
Since, diagonals of a parallelogram bisect each other,
-1+72=2+x2 and -6+22=-5+y2⇒x=4 and y=1
Hence, the coordinates of the fourth vertex D are (4, 1).
Let the coordinates of D be (x, y).
Since, diagonals of a parallelogram bisect each other,
-1+72=2+x2 and -6+22=-5+y2⇒x=4 and y=1
Hence, the coordinates of the fourth vertex D are (4, 1).
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Answer:
x=4 . y=1 .............. ans. ...
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