Question

three vertices of a square PQRS are P(-4,0) ,Q(1,0),R(1,-5).plot the points and find the coordinates of missing vertex S

Answer 1

HELLO DEAR,

[figure is in the attachment]

now,we know the properties of Square
all sides of a square is equal
and all angels are of 90°

GIVEN:- Three vertices of a square PQRS are P(-4,0) ,Q(1,0),R(1,-5),S(x , y).

let the vertices of S(x , y).

so, mid point of QS = PR

mid point formula is $\sf{\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2}}$


$\sf{\frac{1 + x}{2} , \frac{0 + y}{2} = \frac{1 - 4}{2} , \frac{0 - 5}{2}}$​
$\sf{1 + x = -3}$ , $\sf{y = -5}$

⇒x = -4 , y = -5

$\sf{\boxed{HENCE,\;\; point s(-4 , -5)}}$

I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Answer:

GIVEN:- Three vertices of a square PQRS are P(-4,0) ,Q(1,0),R(1,-5),S(x , y).

let the vertices of S(x , y).

so, mid point of QS = PR

mid point formula is

​

,

⇒x = -4 , y = -5

I HOPE ITS HELP YOU DEAR,

THANKS

Step-by-step explanation: