Question

Three workers can finish the Job
in 10 Days. How many
workers
joined to initial three workers
after 2 days if the job was
done 2 days earlier.​

Answer 1

Answer:

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Step-by-step explanation:

12 days

Let us assume that total amount of work required is X.

So 3 workers in 10 days can do X.

Hence 1 worker in 1 day can do X/30.

Now since 1 of them can only work half day, he/she will be able to do only X/60.

So total work received from 3 people in 1 day is:

X/30 + X/30 + X/60 = X/12

Another easier way to solve this is to imagine that there are 2.5 workers.

3 workers can do it in 10 days → 1 worker will be able to do it in 30 days → 2.5 workers will be able to do it in 30/2.5 = 12 days

Answer 2

Concept:

To determine the value of a single unit from a specified multiple, use the unitary method. How to determine the value of one pen, for instance, if the cost of 40 pens is Rs. 400. The unitary approach can be used to complete it. Additionally, after determining the value of a single unit, we can multiply that value by the number of units needed to determine the value of the additional units. The concept of ratio and proportion is mostly applied using this way.

Given:

Three workers can finish the Job in 10 Days

Find:

No.of workers added after 2 days

Solution:

Let the work done by 1 men in 1 day be=1/30

So, amount of work done by 3 men in two days be=1/5

Remaining work= 1-1/5

                          =4/5

Let x men added after 2 days,

So, 3+x men can do work in 6 days=4/5

⇒1/30 x (3+x) x 6=4/5

⇒x=1

Therefore, the no. of workers added be 1

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