Question

Three years ago the population of a town was 50000. If the annual increase during three sucessive years was at the rate 4%,5% and 4% per annum respectively, find the present population

Answer 1

Population 3 years ago = 50000
Present population=50000(1+4/100)(1+5/100)(1+4/100)
=56784

Answer 2

Answer:

The present population is 56784

Step-by-step explanation:

Three years ago the population of a town was 50000.

We are also given that the annual increase during three sucessive years was at the rate 4%,5% and 4% per annum respectively

Increase % in first year = 4%

Population after 1 year = $50000+\frac{4}{100} \times 50000=52000$

Increase in second year = 5%

Population after 2nd year = $52000+\frac{5}{100} \times 52000=54600$

Increase in third year = 5%

Population after 3rd year = $54600+\frac{4}{100} \times 54600=56784$

Hence the present population is 56784