Question

Three years ago, the population of a town was 50000.If the annual increase during three successive years be at the rate of 5%,4%and 3% respectively
What is it's present population

Answer 1

50000×5/100=2500+50000=52500×4/100=2100+52500=54600×3/100=1638+54600=56238

Answer 2

Answer:-

By using Formula of Compound Interest

= Present Population= P ( 1+r/100 )ⁿ

= Present Population= 50000 ( 1+r1 /100) (1+r2 /100) (1+r3 /100)

= Present Population= 50000 (1+5/100) (1+4/100) (1+3/100)

= Present Population= 50000 (100+5 /100) (100+4 /100) (100+3 /100)

= Present Population= 50000 × 105/100 × 104/100 × 103/100

= Present Population= 5×105×104×103 /100

= Present Population= 5623800 / 100

= Present Population=56238