Threshold energy for the photo electron emission of electron from a metal 3.026*10^-15J. if light of 4000A° is used will the electrens be ejected or not
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Answer:
Energy required for photoelectric emission
=hλ
λ=13×10
15
/sec
∴6.6×10
−34
×1.3×10
15
=8.58×10
−19
J
∴ B is correct
1×20
−20
J<thresholdenergy
Explanation:
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