Through A,B and C, lines RQ,PR and QP have been drawn respectively parallel to sides BC,CA and AB of triangle abc show that bc=1/2 qr
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Given,
RQ,PR and QP are parallel to sides BC,CA and AB of triangle ABC.
To Find,
BC=1/2QR
Solution,
From the given data we know,
AR is parallel to BC
AC is parallel to RB
Therefore,
ARBC is a parallelogram,
Hence BC=AR--------(1)
Also, AQCB is a parallelogram
where, BC=AQ--------(2)
After adding (1) and (2),we get,
⇒2BC=AR+AQ
⇒2BC=QR
⇒BC=1/2QR
Hence, in ABC triangle BC=1/2QR.
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