Question

through a rectangular feild of legnth 120 m and breadth 90m, two roads are constructed which are parallel to the sides and cut each other at right angles through the cebtre of the fields. if the width of each road is 5 m find
1. the area covered by thr roads

2. the cost of constructing the roads at the rate of rs 110 per m2

Answer 1

Answer:

through a rectangular feild of legnth 120 m and breadth 90m, two roads are constructed which are parallel to the sides and cut each other at right angles through the cebtre of the fields. if the width of each road is 5 m find

1. the area covered by thr roads

2. the cost of constructing the roads at the rate of rs 110 per m2

Answer 2

Given:-

$\:$

Length of Rectangular field = 90m

Breadth of Rectangular field = 60m

Width of road at centre = 3m.

Need To Find:-

Area of Roads

cost of constructing the roads at the rate of ₹110 per m²

Where:-

L denotes Length

B denotes Breadth

Explanation:-

[Take a look at Attachment] In this Question, We are provided with the length of Rectangular field that is 90m and Breadth that is 60m and there is small road at centre of Rectangular field of 3m that is cuts at right angles through centre of fields.

.

Solution:-

PQ = 3m ; QR = 60m

EF = 90m ; FG = 3m

KL = 3m

⠀⠀

Area of Rectangular Road = QR × PQ

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 60 × 3

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 180m²

Hence, Area of Rectangular road is 180m2

∴Hence,AreaofRectangularroadis180m2

⠀⠀

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Now, We have to find the area Rectangular road EFGH.

Area of Rectangular road EFGH = L × B

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 90 × 3

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 270m²

Hence, Area of Rectangular road is 270m^2

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∴Hence, Area of Rectangular road is 270m2