Through a rectangular field of length 50m and breadth 30m, two roads are
constructed which are parallel to the sides and cut each other at right angles through
the center of the fields. If the width of the road is 5m, find.
a) Area of the field not covered by roads.
b) Cost of construction of roads, after finding its area at the rate of ₹120 per m2.
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Answer:
width =5 m
length of first parallel road 70 m
area of first road 70×5=350 sq.m
length of second road 45 m
area of second road =45×5=225 sq.m
area of the common part of cross road with 5 m width that lies at the
center of the park 5×5 = 225 sq.m
area of roads = area of first road +area of second cross road−common area
=(350+225)−25
=575−25
=550sqm
cost of the construction per sq.m =Rs.105
total cost =550×105=Rs 57750
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