Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find
(i) the area covered by the roads.
(ii) the cost of constructing the roads at the rate of Rs. 110 per m . Please find answer for this question if you can.
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R.E.F. Image.
Given length of field = 90 m
width of field = 60 m.
Area of field =90×60
Area =5400m
2
length of road GEFH = 90 m.
length of road ABCD = 60 m.
width of each road = 3m [Given].
Area of roads =ar(ABCD)+ar.(GEFH)−ar(LIJK)
=90×3+60×3−3×3
=270+180−9
Area of roads =441m
2
.
∴ Area covered by roads =441m
2
.
cost of construction of roads =441×10
Total cost =4410Rs.
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