Math, asked by swaransingh49957, 21 days ago

Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find
(i) the area covered by the roads.
(ii) the cost of constructing the roads at the rate of ₹ 110 per m2.


koi hai​

Answers

Answered by XxOollMrVENOMIloOxX
3

Step-by-step explanation:

Length of the road along the length of the field= 90m

Breadth= 3m

Area of the road= l\times b

=90m\times3m=270m^2

Similarly, the area of the road parallel to the breadth of the field= l\times b

=60m\times3m=180m^2

Area of the common portion= 3m\times3m=9m^2

(i) Area of the two roads

=270m^2+180m^2-9m^2

=450m^2-9m^2=441m^2

(ii) Cost of constructing the roads

=Rs\ 110\times441=Rs\ 48,510

yess , Tiger kaa sath maai bhi zinda hun .XD

bolo kya hua

Answered by pillaripapa3
3

This is your answer..! Mate.

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