Question

Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find (i)the area covered by the roads. (ii)the cost of constructing the roads at the rate of Rs 110 per m2.​

Answer 1

Step-by-step explanation:

(i) the area covered by the roads.

(ii) the cost of constructing the roads at the rate of Rs 110 per m^2

Answer 2

Rectangle

Rectangle has 4 sides. The opposite sides are equal in a rectangle. It has two pairs of parallel sides.

As we went through the concept about Rectangle, Now, Let's move on finding the solution for our question.

We have been given that,

• Length of the rectangular field = 90 m
• Breadth of the rectangular field = 60 m
• Width of the road = 3 m

1) Area covered by the roads.

We know that, The road of width 3 cm lies in both the length and breadth of the rectangular field.

$\sf\implies{(Length\:\times\:3)\:+\:(Breadth\:\times\:3)\:-\:3\:\times\:3}$

$\sf\implies{(90\:\times\:3)\:+\:(60\:\times\:3)\:-\:3\:\times\:3}$

$\sf\implies{270\:+\:180\:-\:9}$

$\sf\implies{450\:-\:9}$

$\sf\implies{441\:cm^2}$

2) The cost of constructing the roads at the rate of Rs. 110 per m².

We have been given that, constructing the roads per meter costs Rs. 110, and we need to find the cost of 441 cm². Total cost would be,

$\sf\implies{441\:\times\:110}$

$\sf\implies{Rs.\:48510}$

Hence, The Area covered by the road is 441 cm² and The total cost is Rs. 48,510.