Through a rectangular field of length 90centimeters and breadth 60centimeters ,two roads are constucted which are parallel to the sides and cut each other at right angles through the centre of fields. If the width of each road is 3centimeters,find the area covered by the road
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PQ = 3 m and PS = 60 m
EH = 3 m and EF = 90 m
KL = 3 m and KN = 3 m
Area of roads = Area of PQRS + Area of EFGH – Area of KLMN [∵ KLMN is taken twice, which is to besubtracted]
= PS x PQ + EF x EH – KL x KN
= (60 x 3) + (90 x 3) – (3 x 3)
= 180 + 270 – 9 = 441 m2
EH = 3 m and EF = 90 m
KL = 3 m and KN = 3 m
Area of roads = Area of PQRS + Area of EFGH – Area of KLMN [∵ KLMN is taken twice, which is to besubtracted]
= PS x PQ + EF x EH – KL x KN
= (60 x 3) + (90 x 3) – (3 x 3)
= 180 + 270 – 9 = 441 m2
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I have answered it earlier
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