Question

through a rectangular field of length 90m and breadth 60m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the field. if the width of each road is 3m, find the area covered by the road

Answer 1

area of road parralel to length =90×3=270
now area of road parallel to breadth=60×3=180
total area will be=270+ 180-3*3( because they are intersecting and 3*3 is coming two times )
270+180-9
=441

Answer 2

Solution:

This is a problem of area and length from mathematics.

In this case,

Area of road parallel to length $=90 \mathrm {m} \times 3 \mathrm{m}=270 \mathrm {sq} \mathrm{m}$

Area of road parallel to breadth $=60 m \times 3 m=180 \mathrm {sq} m.$

But,

Four plots of length and breadth 3 m is counted

twice.  

So, total area will be $=270 \mathrm {sq} \mathrm{m}+180 \mathrm {sq} \mathrm{m}-3 \times 3 \mathrm {sq} \mathrm{m}$

$=270 \mathrm {sq} m+180 \mathrm {sq} \mathrm{m}-9 \mathrm {sq} \mathrm{m}$

$=441 \mathrm {sq} \mathrm{m}$

So, the area of pavement required to fill up the area of the road is

441 sq m.