Question

Through a rectangular field of length 90m and breadth 60m, two roads are constructed which

are parallel to the sides and cut each other at right angles through the centre of the field. If the

width of each road is 3m, find –

i) Area covered by cross roads.

ii) The cost of constructing the roads at the rate of ₹ 110 per m2​

Answer 1

Answer:

area of the roads : 441 sq.m

cost of construction : 48510 ₹

Step-by-step explanation:

60×3=180

(90-3)×3=261

addition of these two areas will give us the total area :

180+261=441

area of the roads is 441sq.m

cost per m. multiplied by the area will give us the total cost to construct the roads :

441×110=48,510

the cost is 48510 ₹

Answer 2

Given:-

Length of Rectangular field = 90m

Breadth of Rectangular field = 60m

Width of road at centre = 3m

Need To Find:-

Area of Roads

cost of constructing the roads at the rate of ₹110 per m²

Where:-

L denotes Length

B denotes Breadth

Explanation:-

[Take a look at Attachment] In this Question, We are provided with the length of Rectangular field that is 90m and Breadth that is 60m and there is small road at centre of Rectangular field of 3m that is cuts at right angles through centre of fields.

$\:$

Solution:-

PQ = 3m ; QR = 60m

EF = 90m ; FG = 3m

KL = 3m

⠀⠀

Area of Rectangular Road = QR × PQ

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 60 × 3

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 180m²

Hence, Area of Rectangular road is 180m2

∴Hence,AreaofRectangularroadis180m2

⠀⠀

_____________________________________

Now, We have to find the area Rectangular road EFGH.

Area of Rectangular road EFGH = L × B

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 90 × 3

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 270m²

Hence, Area of Rectangular road is 270m^2

∴Hence,AreaofRectangularroadis270m2