Math, asked by devashish6, 1 year ago

Through the point (3,4) are drawn two straight lines each inclined at 45° to the straight line x-y=2.Find the equation and also find the area of triangle bounded by three lines

Answers

Answered by aqibkincsem
28
SLOPE OF LINE X-Y=2 IS 1, THIS lines makes an angle OF 45 Degrees with positives x-axis , LET M1 AND 12 BE THE SLOPES of the lines that makes an angle of 45 degrees with x-y =2 . it obvious that one line parallel to x-axis and other parallel to y-axis so one line of x=3 and y=4 . the line x=3 will meet the line x-y=2 at y=1 .the line y=4 the line x=3 will meet the line x-y=2 at x=6 . therefore the arms of right angled triangle are of length of 3 units each therefore the area of triangle is 3^2 square units.
Answered by DIVINEREALM
24

SLOPE OF LINE X-Y=2 IS 1, THIS lines makes an angle OF 45 Degrees with positives x-axis ,

LET M1 AND 12 BE THE SLOPES of the lines that makes an angle of 45 degrees with x-y =2 .

it obvious that one line parallel to x-axis and other parallel to y-axis so one line of x=3 and y=4 .

the line x=3 will meet the line x-y=2 at y=1 .

the line y=4 the line x=3 will meet the line x-y=2 at x=6 .

therefore the arms of right angled triangle are of length of 3 units each

therefore the area of triangle is 3^2 square units.

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