Question

through which of the following points, the graph of the linear equation 3x-2y=0,passes? a, (2/3,-2/3) b, (2/3,3/2) c, (1/3,1/2)

Answer 1

Given: The equation 3x - 2y = 0

To find: through which of the following points, the graph of the linear equation passes?

Solution:

• Now the given points are:

            a, (2/3,-2/3)    b. (2/3,3/2)    c. (1/3,1/2)

• Putting each of them in the equation.

• a. (2/3,-2/3) in 3x - 2y = 0, we get:

            3(2/3) - 2(-2/3) = 0

            2 + 4/3 ≠ 0

            No

• b. (2/3,3/2) in 3x - 2y = 0, we get:

            3(2/3) - 2(3/2) = 0

            2 - 3 ≠ 0

            No

• c. (1/3,1/2) in 3x - 2y = 0, we get:

            3(1/3) - 2(1/2) = 0

            1 - 1 = 0

            Yes.

Answer:

            So the point that satisfies the given equation is c. (1/3,1/2).

Answer 2

Answer:

option c (1/3,1/2) is the right answer.

I hope it may help u

Step-by-step explanation:

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