Thrust exerted by hybolic ram 20cm is 2N Thrust exerted by diameter 30cm will be..........
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3 is the answer of your question
![20 \2 = 30 \x \](https://tex.z-dn.net/?f=20+%5C2+%3D+30+%5Cx+++%5C "20 \2 = 30 \x \")
20 divided by 2 equals to 30 by x (formula
![a 1 \f1 = a2 \f2 \](https://tex.z-dn.net/?f=+a+1+%5Cf1+%3D+a2+%5Cf2+%5C "a 1 \f1 = a2 \f2 \")
20 divided by 2 equals to 30 by x (formula
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hope this helps you quickly
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