Thrust of 'F'N is exerted on an area of 2A and thrust of 3F is exerted on an area of A/2. Find the ratios of their pressure
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Hey, there!
Here's the answer you are looking for
Pressure = Force/Area
☛ In the 1st case,
P1 = F/2A
☛ In the 2nd case,
P2 = 3F/(A/2) = 6F/A
☞ So, the ratio,
Thus, the ratio of pressure is 1:12.
Hope that helps!
Thanks.
Here's the answer you are looking for
Pressure = Force/Area
☛ In the 1st case,
P1 = F/2A
☛ In the 2nd case,
P2 = 3F/(A/2) = 6F/A
☞ So, the ratio,
Thus, the ratio of pressure is 1:12.
Hope that helps!
Thanks.
nalinsingh:
Superb!!
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