Question

Thus, the average speed of Joseph from A to C is 1.90 m/s
We will now calculate the average velocity of Joseph from A to C
Here,
Displacement - 300 m - 100 m
(from A to C) - 200 m
Total time (from A to C) -210 s
(Same as above)​

Answer 1

Answer:

what we have to do I think it is ncert question class 9 ncert but what do we have to calculate.