Thw number of molecules of water in 333 gram of al2(so4)3.18h2o
Answers
Answered by
33
Hello Dear.
Here is the answer---
→→→→→→→→→
Molar Mass of the Al₂SO₄.18H₂O is 474 g/mole
∵ 474 grams of Aluminium Sulphate Crystals Contains 324 grams of Water.
∴ 1 grams ----------→ 324/474 grams of the Water.
∴333 grams --------→ 227.62 grams of Water.
No. of Molecules of Water = (Mass/Molecular mass) × Nₐ.
= (227.62/18) × 6.022 × 10²³.
= 76.15 × 10²³ Molecules.
Thus, the No. of Molecules of Water is 7.15 × 10²³.
→→→→→→→→→
Hope it helps.
Here is the answer---
→→→→→→→→→
Molar Mass of the Al₂SO₄.18H₂O is 474 g/mole
∵ 474 grams of Aluminium Sulphate Crystals Contains 324 grams of Water.
∴ 1 grams ----------→ 324/474 grams of the Water.
∴333 grams --------→ 227.62 grams of Water.
No. of Molecules of Water = (Mass/Molecular mass) × Nₐ.
= (227.62/18) × 6.022 × 10²³.
= 76.15 × 10²³ Molecules.
Thus, the No. of Molecules of Water is 7.15 × 10²³.
→→→→→→→→→
Hope it helps.
Answered by
57
Answer:
Explanation:
Al2(SO4)3.18H2O molecules is=666g
Given molecules of water is = 333g
No.of molecule in water(H2O)=mole×avgdno.×18
=333/666×avgdno.×18
= 1/2×avgdno.×18
=avagdno.×9=Answer
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