Question

ticket numbered from 1to20 are mixed up together and then a ticket drwn at random. what is the probability that the ticket drawn has a number which a a number multiple of 3 or 7​

Answer 1

Answer:

Hello ,

total number of outcomes = 20

for multiple of 3 ,

no. of favorable outcomes = 6

                          probability= 6/20 =3/10

for multiple of 7,

no of favorable outcomes = 2

                          probability= 2/20 =1/10

hope this helps...!

Good luck

Answer 2

Answer:

Step-by-step explanation:

Sample space,

S={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}

n(s)=20

Therefore let the event of getting multiple 3 be A

A={3,6,9,12,15,18}

n(s)=6

p(A) = n(s)/n(A)

=6/20

=3/10

Therefor probability of getting multiple of 3 is 3/10

Now, let the event of getting multiple of 7 be B

B= {7,14}

n(B) = 2

p(B) = n(B)/n(s)

= 2/20

=1/10

Therefore the probability of getting multiple of 7 is 1/10 ✌