Question

Tickets are numbered from 1, 2....1100 and one card is drawn randomly what
is the probability of having 2 as a digit?
a ) 290/1100 b) 291/1100 c) 292/1100 d) 390/1100; Tickets are numbered from 1, 2....1100 and one card is drawn randomly what; is the probability of having 2 as a digit?; a ) 290/1100 b) 291/1100 c) 292/1100 d) 390/1100

Answer 1

here is your answer
total outcomes=1100
favourable outcomes drawn randomly =290
:. probability of having 2 as a digit =
$\frac{290}{1100}$
hope this helps you

Answer 2

Answer:

Option a - $\text{Probability}=\frac{290}{1100}$

Step-by-step explanation:

Given : Tickets are numbered from 1, 2....1100 and one card is drawn randomly.

To find : What  is the probability of having 2 as a digit?

Solution :

Total number of tickets in the bag = 1100.

(1) Number of times 2 appears in 1 - 100 = 19

(2) Number of times 2 appears in 101 - 200 = 20.

(3) Number of times 2 appears in 201 - 300 = 99

(4) Number of times 2 appears in 301 - 400 = 19

(5) Number of times 2 appears in 401 - 500 = 19

(6) Number of times 2 appears in 501 - 600 = 19

(7) Number of times 2 appears in 601 - 700 = 19

(8) Number of times 2 appears in 701 - 800 = 19

(9) Number of times 2 appears in 801 - 900 = 19

(10) Number of times 2 appears in 901 - 1000 = 19

(11) Number of times 2 appears in 1000 - 1100 = 19.

Favorable outcome is 20 + 99 + 9(19)=290

The probability is given by,

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}$

$\text{Probability}=\frac{290}{1100}$

Therefore, Option a is correct.