Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
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Answered by
0
total no. of outcome=20
Favourable outcomes =[3,5,6,9,10,12,15,18,20]=9
Probability =total no of outcomes/favourable outcome
=9/20
Favourable outcomes =[3,5,6,9,10,12,15,18,20]=9
Probability =total no of outcomes/favourable outcome
=9/20
Answered by
3
TOTAL NUMBER OF OUTCOMES [S] = {1, 2, 3, 4, ...., 19, 20}. =20
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
NUMBER OF POSSIBLE.OUTCOMES=9
P(E) =9/20
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
NUMBER OF POSSIBLE.OUTCOMES=9
P(E) =9/20
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