Question

Tickets numbered 1 to 20 are mixed up
and then a ticket is drawn at random.
What is the probability that the ticket
drawn has a number which is a multiple
of 3 or 5?​

Answer 1

No of possible events=9

Total number of events=20

Probability =9/20

Answer 2

Answer:

10/20

Explanation:

p (ticket no which is a multiple of 3 or 5) = 10 /20

as the multiples of 3 or 5 b/w 1 to 20 are 10