Tickets numbered 1 to 20 are mixed up
and then a ticket is drawn at random.
What is the probability that the ticket
drawn has a number which is a multiple
of 3 or 5?
Answers
Answered by
1
No of possible events=9
Total number of events=20
Probability =9/20
Answered by
2
Answer:
10/20
Explanation:
p (ticket no which is a multiple of 3 or 5) = 10 /20
as the multiples of 3 or 5 b/w 1 to 20 are 10
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