Question

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?​

Answer 1

Answer:

There are 20 numbers in them,

n(s)= 20! (S=sample space)

Now,

There are 6 numbers with 3 multiple and 4. numbers with multiple 5

There is only 15 which is multiple of 3 and 5

So,

There are total 9 numbers with multiple of 3 and 5

n(p) = 9!

Therefore,

Probability is 9!÷20!