Question

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?

Answer 1

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

P(E) = n(E)/n(S) = 9/20. ANS

Answer 2

Answer:

So, The probability that the ticket drawn has a number which is a multiple of 3 or 5 = 9/20

Step-by-step explanation:

The tickets are numbered from 1 to 20

Now, we need to find the probability that the ticket drawn is a multiple of 3 or 5

So, total number of outcomes = 20

Numbers which are multiple of 3 or 5 = { 3, 5, 6, 9 , 10 , 12, 15, 18, 20}

No. of numbers which are multiple of 3 or 5 = 9

So, The probability that the ticket drawn has a number which is a multiple of 3 or 5 = 9/20