Question

Tickets numbered from 1 to 20 are mixed up together and than a ticket is drawn at random, then

the probability that the ticket has a number which is a multiple of 3 or 7 is

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Answer 1

Answer:

2/5

Step-by-step explanation:

Tickets: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20

The tickets that has a number that is a multiple of

3: 3, 6, 9, 12, 15, 18

7: 7, 14

So, the total number of tickets that are multiple of 3 or 7 is 8

So, the probability is 8/20 = 4/10 = 2/5

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