Question

Tilak rides on a cycle to a place at speed of 22 kmph and comes back at a speed of 20 kmph. If the time taken by him in the second case is 36 min. more than that of the first case, what is the total distance travelled by him (in km)?
A) 132 km
B) 264 km
C) 134 km
D) 236 km

Answer 1

Hey mate ^_^

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Answer:
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Let the distance travelled by Tilak in first case or second case be 'x' kms.

Now,

From the given data,

$\frac{x}{20} = \frac{x}{22} + 36 \: min$

$\frac{x}{20} = \frac{x}{22} + \frac{3}{5} \: hours$

$d = 132 \: km$

Hence,

The total distance travelled by him,

$= x + x$

$= 132 + 132$

$= 264 \: kms$

Therefore,

Correct option B) 264 kms

#Be Brainly❤️

Answer 2

Heyy mate ❤✌✌❤

Here's your Answer...

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Let the distance travelled by Tilak in first case or second case = d kms

Now, from the given data,

d/20 = d/22 + 36 min

=> d/20 = d/22 + 3/5 hrs

=> d = 132 km.

Hence, the total distance travelled by him = d + d = 132 + 132 = 264 kms.
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