Question

time period of a pendulum is 2 sec and length is 100 cm , Find acceleration due to gravity by using formula of it's time period

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Answer 1

Answer:

On surface of moon, acceleration due to gravity is g/6.Time period of 6 seconds pendulum on earth is 2 seconds.

Explanation:

On earth,2=2π

g

I

on moon ,T

moon

=2π

6

g

I

dividing the above two equations,we

get,T

moon

=2

6

Answer 2

Answer:

The time period of a pendulum is 2 sec and the length is 100 cm. The acceleration due to gravity will be $9.8m/s^2$

Explanation:

• The time period (T) of a simple pendulum is defined by the equation,

        $T = 2\pi \sqrt{\frac{l}{g} }$       ...(1)

       Where,

        g: the acceleration due to gravity.

        Squaring and rearranging equation (1),

        $T^2 = 4\pi ^2(\frac{l}{g} )$

         $\mathrm{g}=4 \pi^{2}\left(\frac{l}{T^{2}}\right)$        ...(2)

         

• In the question, it is given that,

         $T = 2 s$      $l = 100 cm = 1 m$

         We know,

         $\pi = 3.14$

        Then substitute these values into equation(2),

         $\mathrm{g}=4\times \ 3.14^{2}\left(\frac{1}{2^{2}}\right)$

            $= 9.8 m/s^2$

         So we get,

• The acceleration due to gravity (g) = $9.8m/s^2$