Question

Time period of a pendulum is 2 seconds on earth (g = 9.8ms"). Calculate its time on a high altitude where g=4.36 ms.​

Answer 1

Answer:

Time on a high altitude= 2.097sec

Explanation:

$t = 2\pi \sqrt{l \div g}$

t1/t2= (g1/g2)^1/2

t2= ((g2/g1)^1/2 )× t1

t2= 2× 2.19/2.088

t2= 2.097sec