time period of a simple pendulum of length 100 m is 1 second. what is the time period when the length is 64 m?
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Answer:
49.0
T1=2s; l1=100cm; T2=1.4s; l2=?
T2T1=l2l1
∴1.42=l100
Squaring both sides, we get:
1.964=l2100⇒l2=4100×1.96=49.0 cm
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