Question

Time period of an athlete running in a circular track is 15s. Its angular velocity in rad s–1

a) 0.41 b) 41 c) 4.1 d) 0.04​

Answer 1

Answer:

Option a)

Explanation:

Given the information that the time required to complete one track is 15s

Frequency = 1 / time period

F = 1 / 15

F= 0.0667

Now angular velocity is omega / w = 2 pi x f

w = 2 x 3.14 x 0.0667

w = 0.419 rad/s

Hence among the four options given, the correct option is a)

Answer 2

The angular velocity of an athlete is a) 0.41 rad.s⁻¹

Explanation:

The angular velocity is given by the formula:

ω = 2πf

Where,

f = Frequency

The time period is given by the formula:

T = 1/f

On substituting the values, we get,

15 = 1/f

⇒ f = 1/15

∴ f = 0.067 Hz

Now, the angular velocity is:

ω = 2 × 22/7 × 0.067

∴ ω = 0.419 rad/s