time period of oscillation of gas bubble depends upon pressure , density and energy. find dimensionally equation for time period.
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Answered by
2
Given time period T
T∝P
a
d
b
E
c
T=kP
a
d
b
E
c
.....eq(1)
where K is a constant of proportionality and dimensionless quantity.
Inserting the dimensions of Time, pressure, density and Energy in equation (1) we get
[T]=[ML −1 T −2] a
[ML −3] b
[ML 2T −2] c
Equating powers of M ,L,T on both sides we get
0=a+b+c ...(2)
0=−a−3b+2c ..(3)
1=−2a−2c ..(4)
A=-5/6, B=1/2, C=1/3
T∝P
a
d
b
E
c
T=kP
a
d
b
E
c
.....eq(1)
where K is a constant of proportionality and dimensionless quantity.
Inserting the dimensions of Time, pressure, density and Energy in equation (1) we get
[T]=[ML −1 T −2] a
[ML −3] b
[ML 2T −2] c
Equating powers of M ,L,T on both sides we get
0=a+b+c ...(2)
0=−a−3b+2c ..(3)
1=−2a−2c ..(4)
A=-5/6, B=1/2, C=1/3
Answered by
2
Answer:
Explanation:
Given time period T
T∝P ^a D^b E^c
T = k P^a D^b E^c------ (1)
where K is a constant of proportionality and dimensionless quantity.
Inserting the dimensions of Time, pressure, density and Energy in equation (1) we get,
( rest of the explanation sice I am tired of typing I am putting a pic below )
hope it help u
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