Question

Time required to complete a half fraction of a reaction varies inversely to concentration of reactant then the order of the reaction is

Answer 1

Answer:

Time required to complete a half fraction of a reaction varies inversely to concentration  is n=2.

Explanation:

• Time required for the completion a “half fraction of a reaction” is varies inversely to the “concentration of reactant” then the order of reaction is “second order reaction”.

Second order reaction:

• Rate of change in concentration of “product and reactant” is dependent on the second power of concentration of ‘single reactant’ or to ‘first powers’ of the concentration of two reactants.

• For example: $\mathrm{H}_{2}+\mathrm{I}_{2} \rightarrow 2 \mathrm{HI}$

$=\frac{\mathrm{dc}}{\mathrm{dt}}=\mathrm{k}[\mathrm{HI}][\mathrm{HI}]=\mathrm{k}[\mathrm{HI}]^{2}$

From the given,  the time required to complete a half fraction of a reaction varies inversely to concentration as:

$\mathrm{t} \propto \frac{1}{\text { concentration }}$

$t\propto \text { concentration }^{-1}$

-1 = n-1

n=2