Time taken by A alone to finish work is 60% more than A and B together to finish sane work if C is twice twice efficient of B.If B and C together can complete same piece of work in 13(7/9) days how many dats does A alone can finish the same work
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Step-by-step explanation:
B) 24 days
Description for Correct answer:
let the time taken by B = x days
Time taken by c = x2 days
According to questions
1x + 2x = 340
3x = 340
x = 40 days
Let the time taken by A = y days
y = 40y40+y x 160100
40 + y = 64
y = 24 days
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