Question

Time-velocity graph of a body is shown in figure Calculate the following:
(i) Distance travelled in first 10 s
(ii) Acceleration at t = 15 s
(iii) Acceleration between t = 20 s to t = 25s.​

Answer 1

Answer:

1. =30M

2. =O

3. =.2

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Answer 2

Concept:

Acceleration is the rate at which an object's velocity with respect to time changes.

A velocity-time graph shows the direction and rate of motion of an item over a predetermined period of time.

Given:

The time-velocity graph of a body.

Find:

The distance traveled by the body in first $10sec$.

The acceleration of the body at $15\text{sec}$.

The acceleration of the body between $t=20\text{sec}$ and $t=25\text{sec}$.

Solution:

(i) The velocity of the body at $t=10$ is $v=30m/s$

The distance traveled by the body is:

$v=\frac{d}{t}$

$30=\frac{d}{10}$

$d=300 m$

(ii) At $t=15s$

The velocity of the body is $v=30m/s$.

The initial velocity of the body is $u=0m/s$.

Therefore the acceleration of the body is:

$a=\frac{v-u}{t}$

$a=\frac{30-30}{15}$

$a=0m/s^2$

(iii) Now, between $t=20s$ and $t=25s$ the initial velocity is $30m/s$ and the final velocity of the body is $0m/s$.

So, the acceleration:

$a=\frac{v-u}{t_2-t_1}$

$a=\frac{0-30}{25-20}$

$a=\frac{-30}{5}m/s^2$

$a=-6m/s^2$

The distance traveled in first $10s$ is $300m$. The acceleration at $t=15s$ is $0m/s^2$ and the retardation between $t=20s$ and $t=25s$ is $6m/s^2$.

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