Question

Tin and copper are mixed in the ratio 8 : 3. How much tin is needed to mix with

36 g of copper?​

Answer 1

Answer:

Tin : Copper = 8 : 3

(the ratio given is mixed by weight)

therefore,

$\frac{8}{3} = \frac{weight \: of \: tin}{weight \: of \: copper}$

we have,

weight of copper = 36 g

let weight of Tin = T

$\frac{8}{3} = \frac{ t}{36}$

$t = \frac{8 \times 36}{3}$

$t = 96$

Therefore, Weight of Tin = 96g

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Answer 2

Answer:

let tin be 8x and copper be 3x

3x=36g

x=36/3

x=12

Now,

tin=8x=8*12=96g

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