Question

Tina ran around a rectangular garden of length 12 metres and brea
8 metres. Meena ran around a square field of side 11 metres. Who cover
more distance and by how much?​

Answer 1

QUESTION:-

Tina ran around a rectangular garden of length 12 metres and breadth

8 metres. Meena ran around a square field of side 11 metres. Who cover

more distance and by how much?

SOLUTION:-

For rectangle↓

length=12m

Breadth=8m

Perimeter of Rectangle=2(l+b)

=>2(12+8)=2×20= 40m

For Square↓

Side=11m

Perimeter of SQUARE=4a

=>4×11= 44m

${Meena \ covered \ more \ distance, \ By \ 4m}$

$\mathcal{BE \: BRAINLY}$

Answer 2

$\huge{\underline{\underline{\red{\mathfrak{AnSwEr :}}}}}$

$\small{\underline{\blue{\sf{Given :}}}}$

• length (L) = 12 m
• Breadtg (B) = 8 m
• Square Side = 11 m

$\rule{200}{1}$

$\small{\underline{\green{\sf{Solution :}}}}$

We have formula for Perimeter of Rectangle :

$\large \bigstar{\boxed{\sf{Perimeter \: = \: 2(L \: + \: B)}}} \\ \\ \implies {\sf{Perimeter \: = \: 2(12 \: + \: 8)}} \\ \\ \implies {\sf{Perimeter \: = \: 2(20)}} \\ \\ \implies {\sf{Perimeter \: = \: 40}} \\ \\ {\boxed{\sf{Perimeter \:of \: Rectangle \: = \: 40 \: m}}}$

$\rule{150}{0.5}$

And formula for Perimeter of Square is :

$\large \bigstar {\boxed{\sf{Perimeter \: = \: 4(Side)}}} \\ \\ \implies {\sf{Perimeter \: = \: 4 \: \times\:11}} \\ \\ \implies {\sf{Perimeter \: = \: 44}} \\ \\ {\boxed{\sf{Perimeter \: of \: Square \: = \: 44 \: m}}}$

$\rule{200}{2}$

Difference = 44 - 40

Difference = 4 m

∴ Meena covers more distance by 4 m

________________________________

Additional Information :

Square

• Square is 2-D figure.
• All sides and angles square are equal, and angles are of 90° each.
• Diagonals are equal .

Rectangle

• It is also a 2-D figure .
• Opposite sides are equal.
• Angles are of 90° each.
• Diagonals are equal.