Tion: find the value(s) of k for which the equation x2 + 5 kx + 16 = 0 has real and equal roots.
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1
Answer:
Step-by-step explanation:
In pic
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I hope, it helped.
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Answer:
Step-by-step explanation:
x²+5kx +16=0
equal and real root
D=0
b²-4ac=0
(5k)² -4×1×16 =0
25k²- 64 =0
25k²= 64
k²= 64/25
k= ± 8/5
hope it help
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