Question

tiplication of force
15. A man is pulling a trolley on a horizontal road with a force of 100 N making 15° with the
road. The horizontal and vertical components will be

Answer 1

Answer:

Horizontal component of force is Fcosθ

Vertical component of F is Fsinθ 

So, normal reaction N=W−Fsinθ

Friction f=μN=tanϕ(W−Fsinθ)

So, move the body Fcosθ>f

F=cosθf

F=cos(θ−ϕ)Wsinϕ

Explanation:

Horizontal component of force is Fcosθ

Vertical component of F is Fsinθ 

So, normal reaction N=W−Fsinθ

Friction f=μN=tanϕ(W−Fsinθ)

So, move the body Fcosθ>f

F=cosθf

F=cos(θ−ϕ)Wsinϕ

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Answer 2

Answer:

horizontal component is 52.5N

Vertical component is 85.09N