Question

(tl) At 25 "C, the pressure of 10 dm of an ideal gas is decreased from 220 kpa to 100 kpa The volume of
the gas will be​

Answer 1

Answer:

Given P

1

=10;V

1

=22.4dm

3

;P

2

=210KPa;V

2

=?

P∝

V

1

⇒P

1

V

1

=P

2

V

2

⇒V

2

=

P

2

P

1

V

1

=

210

105×22.4

=11.2dm

3

.