TlAl(SO4) 2.x H2O is BCC with a=1.22mm. If the density ofthe solid is 2.32 g/cc then the value of x is
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ln ([A]o/[A]t) = kt
Using the first two, we get:
ln (1.22/0.61) = 6k
0.693 = 6k
k = 0.116 s^-1
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