Tn=2^n+2n^2 find the first five terms
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Answer:6,20,42,72,110
Step-by-step explanation:
T(1)=2(1)+{2(1)}^2=2+4=6
T(2)=2(2)+{2(2)}^2=4+16=20
T(3)=2(3)+{2(3)}^2=6+36=42
T(4)=2(4)+{2(4)}^2=8+64=72
T(5)=2(5)+{2(5)}^2=10+100=110
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