Question

Tne perimeter of a triangles 14a² +20a + 13. Two of its sides are 3a² + 5a + 1 and a²+10a-6 Find its third side.​

Answer 1

Answer:

10a2 +5a+18.

Step-by-step explanation:

As we know that the perimeter of a triangle is the sum of all the sides.

Suppose that the third side of the triangle is X then,

According to the given data in the question-

14a2+20a+13=3a  2 +5a+1+a  2 +10a−6+X

14a2 +20a+13=42+15a−5+X

X=14a  2 +20a+13−(4a  2 +15a−5)

X=14a 2 +20a+13−4a  2 −15a+5

X=10a2 +5a+18