Question

To 100 ml CaCl2 solution containing 6.66g CaCl2, 100 ml of 0.5M Na3PO4 solution is added. The mass of Ca3(PO4)2 precipitated would be ?
A)4.2g
B)5.0g
C)6.2g
D)7.6g

Please answer fast
It’s urgent

Answer 1

Answer:

C) 6.2 g

Explanation:

Amount of CaCl2 = 6.6 g

Moles of Na3PO4 = 0.5 M

Now,

We have to find the molar mass of Na3PO4 = G.M / M. M

= 226 / 0.5

= 4.52 g

= 4.52 / 6.6

= 6.2 g

So, answer is 6.2 g

Hope this will help and make understand to you!

Thank you!

Answer 2

Answer:

c)6.2g

Explanation:

I hope the answer is correct